Question

Find the equation of a line which divides the join of (1,0) and (3,0) in the ratio 2:1 and perpendicular to it

Answer 1

I hope it helps to you...

Answer 2

To find:

The equation of a line which divides the join of (1, 0) and (3, 0) in the ratio 2 : 1 and perpendicular to it

Step-by-step explanation:

Step 1. Finding the point on the join of (1, 0) and (3, 0), where the line is divided into 2 : 1

The required point is

( (1 × 1 + 2 × 3)/(2 + 1), (0 × 1 + 0 × 2)/(2 + 1) )

i.e., ( (1 + 6)/3, (0 + 0)/3 )

i.e., (7/3, 0/3)

i.e., (7/3, 0)

Step 2. Line that passes through (1, 0) and (3, 0)

The equation of the line that passes through (1, 0) and (3, 0) is given by

(y - 0)/(0 - 0) = (x - 1)/(1 - 3)

or, y/0 = (x - 1)(- 2)

or, y = 0

Step 3. Finding the perpendicular line of y = 0

The equation of the line perpendicular to y = 0 is

x = k

Now this line passes through (7/3, 0). Then,

7/3 = k

Thus the required equation is

x = 7/3

or, 3x = 7

Answer:

The equation of a line which divides the join of (1, 0) and (3, 0) in the ratio 2 : 1 and perpendicular to it is 3x = 7.

Read more on Brainly.in

a straight line is parallel to the line 3x-y-3=0 and 3x-y+5=0 and lies between them find equation of the line if it's di...

- https://brainly.in/question/12891227