Question

find the equation of a line,which has the Y intercept 4 and is parallel to the line 2x-3y-7=0. find the coordinates of the point where it cuts the x-axis

Answer 1

line parallel to 2x-3y-7=0
is given by
$2x - 3y + c = 0 \\ y \: intercept \: = 4 \\ when \: x = 0 \: \: \: \: y = 4 \\ put \: above \\ 2(0) - 3(4) + c = 0 \\ c = 12 \\ \: therefore \: eqn \: becomes \: \\ 2x - 3y + 12 = 0$


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Answer 2

Answer:

Step-by-step explanation:

Y=4

Thats mean

X=0

So

Put the value of x and y in given eq

2×0-3×4=k

0-12=k

K=-12

parallel eq will be

2x-3y=-12

so

If y=0

than

2x-3×0=-12

2x-0=-12

2x=-12

x=-6

So coordinates would be

(-6,0)

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