Question

find the equation of a line which passes through (5,7) and makes intercepts on the axes equal in magnitude but opposite in sign
pls help me ​

Answer 1

SOLUTION

TO DETERMINE

The equation of a line which passes through (5,7) and makes intercepts on the axes equal in magnitude but opposite in sign

EVALUATION

Here it is given that the line makes intercepts on the axes equal in magnitude but opposite in sign

Let the equation of the required line is

$\displaystyle \sf{ \frac{x}{a} + \frac{y}{ - a} = 1}$

Which can be rewritten as

$\displaystyle \sf{ x - y = a} \: \: \: ......(1)$

Now the line given by the equation (1) passes through the point (5,7)

So the point (5,7) satisfies the equation (1)

$\therefore \: \sf{5 - 7 = a}$

$\implies \sf{a = - 2}$

Hence the required equation of the line is

$\sf{x - y = - 2}$

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Answer 2

Step-by-step explanation:

it is very easy bro so it maths is not tuf