Question

Find the equation of a line which passes through (pcosa, p sina) and making an
angle of (90 + a) with the positive direction of x-axis.​

Answer 1

Answer:

We can use the normal form of equation of a straight line. This is:

xcosα + ysinα = p

Where α = angle made with +ve x axis

p = Perpendicular distance from origin to the given line

Now, we can say:

pcosαcos(90+α) + psinαsin(90+α) = p

-pcosαsinα + psinαcosα = p

p = 0

So the equation of line is:

ycosα - xsinα = 0

ycosα = xsinα

y = xtanα

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