Question

find the equation of a line which passes through the point (2,2) and the slope is 1​

Answer 1

$\LARGE{ \underline{\underline{\green{ \sf{Required \: answer:}}}}}$

We know that the equation of line passing through a point (x0, y0) with slope m is given by:

$\large{ \boxed{ \sf{y - y0 = m(x - x0)}}}$

We have,

• Slope = 1
• Coordinates of the point = (2,2)

Plugging in the given Equation:

⇒ y - 2 = 1(x - 2)

⇒ y - 2 = x - 2

⇒ y - x = -2 + 2

⇒ y - x = 0

⇒ x - y = 0

Hence,

• The desired equation is x - y = 0

Explore more!!

• We also use the formula: y = mx + b when m is the slope given and b is the y-intercept.

• y-intercept is the point where the line intersects the y-axis. And Slope = Change in y / Change in x.

Answer 2

$\huge\sf\boxed{\green{Question:-}}$

find the equation of a line which passes through the point (2,2) and the slope is 1

$\huge\underline\bold\blue{solution}$

we know that ,

☞the equation of line passing through point (x0,y0) whose slope is m is

(y-y0)=m(x-x0)

Thus the equation of line passing through the point (2,2) whose slope is 1.

putting the values in the equation,

➱ y - 2 = 1(x - 2)

➱ y - 2 = x - 2

➱ y - x = -2 + 2

➱ y - x = 0

➱ x - y = 0

hence verified ✅