Question

Find the equation of a line whose intercepts on the x and y axes are 4, –6

Answer 1

3x-2y=12 is the required answer

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Answer 2

Answer:

      The required equation is "3x - 2y - 6 = 0"

Step-by-step explanation:

        G.T.,

             a = 4 and b = -6

        W.K.T.,

             $\frac{x}{a} +\frac{y}{b} = 1$

             $\frac{x}{4} +\frac{y}{-6} = 1$

             $\frac{-6x + 4y}{-12} = 1$

             $-6x+4y=-12$

             $6x - 4y-12=0$

             $2(3x-2y-6)=0$

             $3x-2y-6=0$

∵ Hence, our required equation is "3x - 2y - 6 = 0"