Question

Find the equation of a line whose slope is the additive inverse of the line 3x-4y=6 and passing through a point on x axis whose abscissa is -1.

Answer 1

Answer:

Let the line be L' and it's slope be m'.

Eqn of given L:

» 3x - 4y = 6

» m = 3/4

Now, 3/4 + m' = 0

Therefore, m' = -3/4

L' passes through point (-1, 0)

Therefore, eqn of L' is

» y - 0 = m (x + 1)

» y = -3 (x + 1)/4

» 3x + 4y + 3 = 0, is the eqn of the required line.