Question

Find the equation of a line whose y-intercept is
and which is perpendicular to 2x - 3y + 5 = 0


sol: sorry i don't no​

Answer 1

Answer:

below ans helps you

Step-by-step explanation:

2x + 3y + 10 = 0

=> 3y = - 2x - 10

=> y = - 2x/3 - 10/3

Clearly, yhe slope of this line is - 2/3. So the slope of the line perpendicular to this line will be 3/2.

So the equation of the perpendicular line is of the form y = 3x /2 + b.

Now, y intercept is b (put x=0).

Putting y = 0, we get the x intercept.

3x/2 + b =0

Therefor, x intercept is - 2b/3.

But, from the condition we know that b = - 2b/3 + 2.

Solving this equation, b + 2b/3 = 2

=> 5b = 6

=> b = 6/5.

Substituting b in the equation derived above, we have the equation of the required line

y = 3x/2 + 6/5

Answer 2

Answer:

$y =( 3x \div 2) + (6 \div 5)$

is the equation of a line.