Question

find the equation of A locus of a point which is equidistant from the point A(-3, 2) and B(0, 4)​

Answer 1

Answer:

let P(x,y).

a/q PA=PB

$(x + 3) {}^{2} + (y - 2) {}^{2} = (x - 0) { }^{2} + (y - 4) {}^{2}$

${x}^{2} + 6x + 9 + {y}^{2} - 4y + 4 = {x}^{2} + {y}^{2} - 8y + 16$

$6x + 4y = 3$