find the equation of a normal to a given curve y=x^2-3x+2 at (2,3)
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Answer:
Step-by-step explanation:
Step-by-step explanation:
x² + y² - 3x + 4y - 31 = 0 putting (-2) in x and 3 in y
(-2)² +3² −3 × (−2) + 4 × 3 − 31 = 0
4+9+6+12 - 31-0
31- 31 = 0
0=0
Answered by
0
Answer:
hi
Step-by-step explanation:
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