Question

find the equation of a parabola with focal points (-8,-2) and directrix Y-2x+9=0

Answer 1

Answer:

PS =PM

PS is distance of point from focus

PM is perpendicular distance of point from a line

√(x+8)^2 + ( y+2)^2 = | -2x+y +9 / √ 4+ 1 |

Squaring on both side

X^2 +64 + 16x + y^2 + 4 y + 4 = (-2x+y+9)^2 / 5

= 4x^2 +y^2 +81 - 4xy + 18y - 36 x /5

5x^2 + 5y^2 + 20y + 80 x + 340 = 4x^2 + y^2 -4xy +18y -36x +81

Step-by-step explanation:

Answer 2

Answer:

Hope this helps you...

If you don't understand then go through this website: https://www.algebra.com/algebra/homework/Quadratic-relations-and-conic-sections/Quadratic-relations-and-conic-sections.faq.question.1087649.html