Question

Find the equation of a plane passing through the points and perpendicular to the lines

Answer 1

Step-by-step explanation:

The plane is perpendicular to the line. Therefore the normal of the plane is the dc of the line. So just put it in the equation a(x-x1) + b(y-y1) + c(z-z1) = 0. Where a,b and c are the dc of the line and xx, y1 and z1 are the coordinates of the point.

Hope this helps you