Question

Find the equation of a straight line cutting off an intercept -2 and 3

Answer 1

Answer:

Equation to the straight line cutting off an intercept 2 from negative direction of the axis of y and inclined at 30∘30∘ to the positive direction of axis of x

Answer 2

$\mathtt{ \huge \fbox{SOLUTION : }}$

Given ,

x intercept (b) = -2

y intercept (a) = 3

We know that , the intercept form is given by

$\sf \large \fbox{ \frac{x}{a} + \frac{y}{b} = 1 }$

Substitute the values , we obtain

$\sf \mapsto - \frac{ x}{2} + \frac{y}{3} = 1 \\ \\ \sf \mapsto - 3x + 2y = 6 \\ \\ \sf \mapsto - 3x + 2y - 6 = 0$

Hence , -3x + 2y - 6 = 0 is the required equation of line