Question

find the equation of a straight line cutting off an intercept-2 from the y-axis and being equally inclined to the -axis


please help me class 11th chapter 10th ex 10 d
modern math
question no 7 ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

$\[ \begin{array}{l} \text{Solution : Since, the required line is equally inclined with co-ordinate axis, } \\ \qquad \: \qquad\text{ therefore, it makes either an angle of \( 45^{\circ} \)} \\ \qquad \qquad \text{ or \( 135^{\circ} \) with the \( X \)-axis.} \\ \\ \text { So, its slope is } \tt m=\tan 45^{\circ} \Rightarrow m=1 \\ \text { or } \quad \tt m=\tan 135^{\circ} \Rightarrow m=-1 \\ \text { Y-intercept, } \tt \: c=-2 \end{array} \]$

$\color{red} \[ \begin{aligned} \tt \: y & \tt \: =m x+c & \\ \\ \text { i.e., } & \tt y =1 \cdot x-2& \text { or } \tt y=-1 \cdot x-2 \\ \\ & \tt \: y =x-2 &\text { or } \tt y=-x-2 \\ \\ \Rightarrow & \tt x-y-2 =0& \text { or } \tt x+y+2=0 \end{aligned} \]$