Question

Find the equation of a straight line parallel to X axis and passing through the point of intersection of the

lines 4x + 5y = 13 and x – 8y + 9 = 0.​

Answer 1

Answer:

first find the point of intersection.

since it is parallel to x axis so the equation becomes y=y coordinate of point of intersection

Answer 2

• The equation of the line is x = 59/37 = 37x - 59 = 0

Explaination :

Given :-

4x + 5y = 13

x - 8y + 9 = 0

Let,

4x + 5y - 13 = 0 ------- (1)

x - 8y + 9 = 0 -------- (2)

Solving (1) & (2) :-

x y 1

5 -13 4 5

-8 9 1 -8

x y 1

_____ = _____ = _____

45 - 104 -13 - 36 -32 - 5

⟹ x / -59 = y / -49 = 1 / -37

⟹ x = 59 / 37, y = 49 / 37

Therefore, the point of intersection (x, y) = (59/37, 49/37)

The equation of line parallel to Y axis is x = c

It passes through (x, y) = (59/37, 49/37). Therefore, c = 59/37

• Hence, The equation of the line is x = 59/37 = 37x - 59 = 0