Question

Find the equation of a straight line passing through (5, – 3) and (7,- 4).​

Answer 1

Answer:

x+2y+1=0

Step-by-step explanation:

Let A=(5,-3)=(x1,y1)

B=(7,-4)=(x2,y2)

WKT,

Slope,m=y2-y1/x2-x1

=-4+3/7-5

m =-1/2

Req.equ:

y-y1=m(x-x1)

y+3=-1/2(x-5)

2y+6=-x+5

x+2y+1=0