Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes
Answers
Answer:
EXPLANATION.
Equation of a straight lines passing through (-8,4).
making equal intercept on the co-ordinate axis.
As we know that,
Let we assume that x-intercept & y-intercept = t
equation of line,
⇒ x/a + y/b = 1.
We can write as,
⇒ x/t + y/t = 1.
⇒ -8/t + 4/t = 1.
⇒ -8 + 4 = t.
⇒ -4 = t.
Put the value of t = -4 in equation, we get.
⇒ x/-4 + y/-4 = 1.
⇒ x + y = -4.
⇒ x + y + 4 = 0.
MORE INFORMATION.
Equation of straight lines parallel to axes.
(1) = Equation of x-axis ⇒ y = 0.
(2) = Equation of a line parallel to x-axes at a distance of b ⇒ y = b.
(3) = Equation of y-axis ⇒ x = 0.
(4) = Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.
Αηѕωєя :
Equation of a straight lines passing through (-8,4).
making equal intercept on the co-ordinate axis.
As we know that,
Let we assume that x-intercept & y-intercept = t
equation of line,
⇒ x/a + y/b = 1.
We can write as,
⇒ x/t + y/t = 1.
⇒ -8/t + 4/t = 1.
⇒ -8 + 4 = t.
⇒ -4 = t.
Put the value of t = -4 in equation, we get.
⇒ x/-4 + y/-4 = 1.
⇒ x + y = -4.
⇒ x + y + 4 = 0.