Question

Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes​

Answer 1

Answer:

EXPLANATION.

Equation of a straight lines passing through (-8,4).

making equal intercept on the co-ordinate axis.

As we know that,

Let we assume that x-intercept & y-intercept = t

equation of line,

⇒ x/a + y/b = 1.

We can write as,

⇒ x/t + y/t = 1.

⇒ -8/t + 4/t = 1.

⇒ -8 + 4 = t.

⇒ -4 = t.

Put the value of t = -4 in equation, we get.

⇒ x/-4 + y/-4 = 1.

⇒ x + y = -4.

⇒ x + y + 4 = 0.

                                                                                         

MORE INFORMATION.

Equation of straight lines parallel to axes.

(1) = Equation of x-axis ⇒ y = 0.

(2) = Equation of a line parallel to x-axes at a distance of b ⇒ y = b.

(3) = Equation of y-axis ⇒ x = 0.

(4) = Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.

Answer 2

Let the x-intercept "a"

The equation of a line is

_ _/a=1

The line passes through the point (-8,4)

_. _. =1

a. a

$\frac{ - 8 + 4}{a} = 1$

-4=a

The equation of a line is

$\frac{x}{ - 4} + \frac{y}{ - 4} = 1$

Multiply by -4

x+y=-4

x+y+4=0

The equation of the line is x+y+4=0