Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes
Answers
Answer:
EXPLANATION.
Equation of a straight lines passing through (-8,4).
making equal intercept on the co-ordinate axis.
As we know that,
Let we assume that x-intercept & y-intercept = t
equation of line,
⇒ x/a + y/b = 1.
We can write as,
⇒ x/t + y/t = 1.
⇒ -8/t + 4/t = 1.
⇒ -8 + 4 = t.
⇒ -4 = t.
Put the value of t = -4 in equation, we get.
⇒ x/-4 + y/-4 = 1.
⇒ x + y = -4.
⇒ x + y + 4 = 0.
MORE INFORMATION.
Equation of straight lines parallel to axes.
(1) = Equation of x-axis ⇒ y = 0.
(2) = Equation of a line parallel to x-axes at a distance of b ⇒ y = b.
(3) = Equation of y-axis ⇒ x = 0.
(4) = Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.
Answer:
Explanation:
let the total work be 1
r admit for 1/6 share
remaing 1-1/6=5/6
p new ratio will 5/6*4/7=20/42
q new ratio will 5/6*3/7=15/42
r new share will 1/6 multiply by 7 numerator and deminometer =7/42
p:q:r =20:15:7
sr ratio old-new
p 4/7-20/42 =4/42
q 3/7-15/42 = 3/42
4:3 is sacrifice ratio