Biology, asked by Anonymous, 3 months ago

Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes​

Answers

Answered by Anonymous
6

Answer:

EXPLANATION.

Equation of a straight lines passing through (-8,4).

making equal intercept on the co-ordinate axis.

As we know that,

Let we assume that x-intercept & y-intercept = t

equation of line,

⇒ x/a + y/b = 1.

We can write as,

⇒ x/t + y/t = 1.

⇒ -8/t + 4/t = 1.

⇒ -8 + 4 = t.

⇒ -4 = t.

Put the value of t = -4 in equation, we get.

⇒ x/-4 + y/-4 = 1.

⇒ x + y = -4.

⇒ x + y + 4 = 0.

                                                                                         

MORE INFORMATION.

Equation of straight lines parallel to axes.

(1) = Equation of x-axis ⇒ y = 0.

(2) = Equation of a line parallel to x-axes at a distance of b ⇒ y = b.

(3) = Equation of y-axis ⇒ x = 0.

(4) = Equation of a line parallel to y-axes and at a distance of a ⇒ x = a.

Answered by Anonymous
8

Answer:

Explanation:

let the total work be 1

r admit for 1/6 share

remaing 1-1/6=5/6

p new ratio will 5/6*4/7=20/42

q new ratio will 5/6*3/7=15/42

r new share will 1/6 multiply by 7 numerator and deminometer =7/42

p:q:r =20:15:7

sr ratio old-new

p 4/7-20/42 =4/42

q 3/7-15/42 = 3/42

4:3 is sacrifice ratio

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