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Find the equation of a straight line passing through (-8,4) and making equal intercepts on the coordinate axes​

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Answered by Anonymous
2

Answer:

Answer:

EXPLANATION.

Equation of a straight lines passing through (-8,4).

making equal intercept on the co-ordinate axis.

As we know that,

Let we assume that x-intercept & y-intercept = t

equation of line,

⇒ x/a + y/b = 1.

We can write as,

⇒ x/t + y/t = 1.

⇒ -8/t + 4/t = 1.

⇒ -8 + 4 = t.

⇒ -4 = t.

Put the value of t = -4 in equation, we get.

⇒ x/-4 + y/-4 = 1.

⇒ x + y = -4.

⇒ x + y + 4 = 0.

                                                                                         

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Answered by Anonymous
2

Equation of a straight lines passing through (-8,4).

making equal intercept on the co-ordinate axis.

As we know that,

equation of line,

Let we assume that x-intercept & y-intercept = t

⇒ x/a + y/b = 1.

We can write as,

⇒ x/t + y/t = 1.

⇒ -8/t + 4/t = 1.

⇒ -8 + 4 = t.

⇒ -4 = t.

Put the value of t = -4 in equation, we get.

⇒ x/-4 + y/-4 = 1.

⇒ x + y = -4.

⇒ x + y + 4 = 0.

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