Question

Find the equation of a straight line passing through a point (2, -5) and making an interpreet of -5 on y-axis​

Answer 1

Answer:

y=-5 or y+5=0

Step-by-step explanation:

Given,a line eq.passes through the point (2,-5)and makes a y-intercept of -5

we know that,

the eq. of straight line is y=mx+c

where mis slope

c is y-intercept

c=-5

so, we have

y=mx-5

Now,this line eq.satisfy the point (2,-5)=(x,y)

-5=m(2)-5

-5+5=2m

2m=0

m=0

hence,the eq. of the line is y=mx-5

y=(0)x-5

y=-5 (or) y+5=0