Question

*Find the equation of a straight line passing through point (4, 3) with slope 2.*

1️⃣ 2x − y + 5 = 0
2️⃣ 2x − y − 5 = 0
3️⃣ y + 2x = −5
4️⃣ −2x − y = −5


please answer fast ​

Answer 1

Step-by-step explanation:

Let's assume the point of intersection of the line 2x+5y−4=0 and x - axis be (x,0)

Now, substituting the value y=0 in the equation, we have

2x+5(0)−4=0

2x−4=0

x=24=2

Hence, the co-ordinates of the point of intersection is (2,0)

Also given, line equation : 3x−7y+8=0

7y=3x+8

y=(73)x+78

So, the slope (m)=73  

We know that the slope of any line parallel to the given line will be the same.

So, the equation of the line having slope 73 and passing through the point (2,0) will be

y−0=(73)(x−2)

7y=3x−6

3x−7y−6=0

Thus, the required line equation is 3x−7y−6=0