find the equation of a straight line passing through the origin and through the point of intersection of the lines 5x+7y=3 and 2x-3y=7
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find point of intersection using simultaneous equation.
5x+7y=3 —1
2x-3y=7 —2
From 2,
x = 1.5y + 3.5 —2a
Sub 2a into 1,
5(1.5y + 3.5) + 7y = 3
7.5y + 17.5 + 7y = 3
14.5y = -14.5
y = -1 — 3
Sub 3 into 2,
2x + 3 = 7
x = 2
Thus point of intersection is (2,-1).
Let equation of straight line be y = mx+c
c = 0
Sub (2,-1) into y=mx
-1 = 2m
m = -0.5
Answer: y=-0.5x
5x+7y=3 —1
2x-3y=7 —2
From 2,
x = 1.5y + 3.5 —2a
Sub 2a into 1,
5(1.5y + 3.5) + 7y = 3
7.5y + 17.5 + 7y = 3
14.5y = -14.5
y = -1 — 3
Sub 3 into 2,
2x + 3 = 7
x = 2
Thus point of intersection is (2,-1).
Let equation of straight line be y = mx+c
c = 0
Sub (2,-1) into y=mx
-1 = 2m
m = -0.5
Answer: y=-0.5x
zayD1:
bro its a wrong answer
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