Question

find the equation of a straight line passing through the intersection of
$2x + 5y - 4 = 0$
with x axis and parallel to the lines
$3x - 7y + 8 = 0$
THE FIRST ONE TO ANSWER WILL BE MARKED BRAINLIEST

Answer 1

Let m be the slope of the required line
If the line is parallel to 3x-7y+8=0 then their slopes must be equal. So the slope of 3x-7y+8=0 is 3/7. So m=3/7.
Now 2x + 5y - 4 = 0 intersects the x axis at (2,0). [put y=0 in 2x + 5y - 4 = 0].
Using slope point form
y-0=3/7(x-2)
7y=3x-6
3x-7y-6=0 is the required line