Question

find the equation of a straight line passing through the point(2,-5)and parallel to the line x+y=2and also find the area of the triangle formed by this with the coordinate axes​

Answer 1

Step-by-step explanation:

We have

2x−3y=7⇒y=23x=73

∴ slope of the given line=23 and the slope of a line parallel to the given line=23 .

Now, the equation of the line slope 23 and passing through the points (2,-5) is given by

y−(−5)x−2=23⇒y+5x−2=23 [∴(y−y1)(x−x1)=m]

⇒3(y+5)=2(x−2)

⇒2x−3y−19=0, which is the required equation.