Question

find the equation of a straight line passing through the point (3,2) and is perpendicular tothe line y-x=0

Answer 1

Hi Mate !!!

When two lines are perpendicular product of their slopes = -1

Equation of line passing through ( 3,2) is

y - 3 = m ( x - 3 )

m is slope

Slope of y -x = 0 is m1 = 1

m × m1 = 1

m = 1


so, equation of line is

y -2 = 1 ( x - 3 )

y - 2 = x - 3

y -x = -1

Have a nice day

Answer 2

Step-by-step explanation:

as y-x=0

x-y=0

form of any line perpendicular to ax+by+c=0 is bx-ay+k=0

-x-y+k=0

passing through points=(3,2)

-3-2+k=0

-5+k=0

k=5

hence line will be -x-y+5=0 OR x+y-5=0