Question

Find the equation of a straight line passing
through the mid point of a
a line segment
joining the points (1,-5) 14, 2) and partallel to
ch X axis
Solution​

Answer 1

Answer:

y=-3/2

Step-by-step explanation:

mid point of line segment joining the points (1,-5),(14,2) is (1+14/2,-5+2/2)=(15/2,-3/2) because we use mid point formula that is (x1+x2/2,y1+y2/2)

now we have to find line passing through (15/2,-3/2) and parallel to X axis.

parallel to X axis have the slope 0.

line passing through point (x1, y1) and having slope m have equation (y-y1)=m(x-x1) in our question x1=15/2,y1=-3/2,m=0 therefore our line equation is

(y-(-3/2)) =0(x-15/2)

y+3/2=0

y=-3/2 is the required line equation.

THEREFORE LINE EQUATION IS y=-3/2.

I hope you are satisfied by my answer.