Question

find the equation of a straight line through (4,5(and parllel to 2x-3y-5=0​

Answer 1

Step-by-step explanation:

Equation of the line parallel to line

2x−3y−5=0

2x−3y+c=0

It passes through point (4,5)

then 2×4−3×5+c=0

⇒8−15+c=0

⇒c=7

Hence, equation of straight line is

2x−3y+7=0