find the equation of a straight line through the point (4,3) which makes an angle of 45 degree with the straight line 3x-y+6=0
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Step-by-step explanation:
this is very easy question
slope of line inclined theta with slope of line m = m+-tantheta / 1-+mtantheta
slope of line = 3
tantheta = 1
slope of line which is inclined 45 with other = 3+-1 / 1-+3
slope = 4/-2 and 2/4 or -2 and 1/2
apply point slope form now
y-3 = -2(x-4)
y-3 = -2x+8
2x+y-11 = 0
y-3 = 1/2(x-4)
2y-6 = x-4
x-2y+2 = 0
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