Question

Find the equation of a straight line which has slope minus 5 by 4 and passing through the point (-1,2).

Answer 1

Given :

• Slope ( m ) = - 5/4

• Coordinates of points ( x1 , y1 ) = ( - 1 , 2 )

To Find :

• Equation of the straight line

Solution :

Point slope of line is

$\large \implies \boxed{ \boxed{ \sf y - y_1 = m(x - x_1)}}$

Substitute values in formula

$\implies \sf y - 2 = - \frac{5}{4}(x - ( - 1)) \\ \\\implies \sf y - 2 = - \frac{5}{4}(x + 1) \\ \\ \implies \sf y - 2 = \frac{ - 5x}{4} - \frac{5}{4} \\ \\ \implies \sf y = \frac{ - 5x}{4} - \frac{5}{4} + 2 \\ \\ \implies \sf y = \frac{ - 5x}{4} - \frac{5 + 8}{4} \\ \\ \implies \sf y = \frac{ - 5x}{4} - \frac{13}{4} \\ \\ \implies \sf \frac{ 5x}{4} + y +\frac{13}{4} = 0\\ \\ \sf\implies \frac{ 5x + 4y + 13}{4} = 0 \\ \\ \large \implies \boxed{ \boxed{\sf 5x + 4y +13= 0 }}$

Answer 2

Step-by-step explanation:

here is your answer

hope THIS will help