Question

Find the equation of a straight line which is parallel to the line 3x −7y = 12 and passing through the point (6,4). *

a.)3x −7y +10 = 0 .

b.)3x −7y -10 = 0

c.)3x +7y +10 = 0 .

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Answer 1

Answer:

Option a) 3x - 7y + 10 = 0 is the equation of the parallel straight line.

Step-by-step explanation:

A straight line that is parallel to the line 3x - 7y = 12 can have an equation:

3x - 7y = k, where k is a constant to be determined.

Now, the parallel straight line passes through (6,4).

Putting the X and Y coordinates in the equation:

3(6) - 7(4) = k

∴ k = 18 - 28 = -10

∴ The equation is 3x - 7y = -10 =>3x - 7y + 10 = 0

Answer 2

Answer:

the ans is 3x-7y+10=0 ...