Question

find the equation of a straight line which is parallel to the line 3x-7y-12 and passing through the point (4,6).​

Answer 1

Hey Buddy..

Here is your solution..

Answer:7x-3y-10=0

Step-by-step Explanation:

Given line is 3x-7y-12.

3x=7y+12

x=7/3y+12/3

x=7/3y+4

Hence, Slope of this line(m) is 7/3.

As we know, slope of parallel line are same.

therefore,

Equation of a straight line passing through (4, 6),

y-y1=m(x-x1)

y-6=7/3(x-4)

3(y-6)=7(x-4)

3y-18=7x-28

7x-3y-28+18=0

7x-3y-10=0

HOPE IT HELPS..

BE BRAINLY✌✌

Answer 2

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