Question

Find the equation of a straight line which passes through the points $(1,2)$ and $(4,6)$.
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Answer 1

Solution :-

In the question, we are given two coordinates and we are asked to find the straight line equation passing through the given points.

We will use two point form of straight line to find the required equation.

Let's assume that,

• $(x_1,y_1) = (1,2)$
• $(x_2,y_2) ,= (4,6)$

Two point form of straight line,

$\boxed{(y-y_1) = \dfrac{y_2-y_1}{x_2-x_1}(x-x_1)}$

By substituting the given values, we get :

$\longrightarrow(y-2) = \dfrac{6 - 2}{4 - 1}(x-1)$

$\longrightarrow(y-2) = \dfrac{4}{3}(x-1)$

$\longrightarrow3(y-2) = 4(x-1)$

$\longrightarrow3y - 6 = 4x - 4$

$\longrightarrow3y - 6 - 4x + 4 = 0$

$\longrightarrow \underline{\underline{3y - 4x - 2 = 0}}$

This is the required equation of straight line.