Question

find the equation of a straight lines, making the y- intercept of 7 and angle between the line and the y-axis is 30°​

Answer 1

Answer:

$\huge\underline\bold\red{Solution!!}$

these are two straight lines making 30° with the y-axis

from the attachment,it is clear that the two lines make the angles 60° and 120° with the x-axis

$let \: m1 \: be \: tan60° = \sqrt{3} \: and \\ m2 \: be \: tan120° = tan(180° - 60°) \\ = - tan60° = - \sqrt{3 } \\ m1 = \sqrt{3},m2 = - \sqrt{3 } \: and \: b =7 \\ \\ equations \: of \: lines \: are \: y = m1x + b \\ and \: y = m2x + b \\ y = \sqrt{3} x + 7 \: and \: y = - \sqrt{3} x + 7$

HOPE IT HELPS YOU ❤️

Answer 2

Step-by-step explanation:

Answer:

\huge\underline\bold\red{Solution!!}

Solution!!

these are two straight lines making 30° with the y-axis

from the attachment,it is clear that the two lines make the angles 60° and 120° with the x-axis

\begin{gathered}let \: m1 \: be \: tan60° = \sqrt{3} \: and \\ m2 \: be \: tan120° = tan(180° - 60°) \\ = - tan60° = - \sqrt{3 } \\ m1 = \sqrt{3},m2 = - \sqrt{3 } \: and \: b =7 \\ \\ equations \: of \: lines \: are \: y = m1x + b \\ and \: y = m2x + b \\ y = \sqrt{3} x + 7 \: and \: y = - \sqrt{3} x + 7\end{gathered}

letm1betan60°=

3

and

m2betan120°=tan(180°−60°)

=−tan60°=−

3

m1=

3

,m2=−

3

andb=7

equationsoflinesarey=m1x+b

andy=m2x+b

y=

3

x+7andy=−

3

x+7

HOPE IT HELPS YOU ❤️