find the equation of any two lines passing through the point (- 6,2)
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the equations are:-
x+3y = 0
x-3y+12 = 0
x+3y = 0
x-3y+12 = 0
Rockeyverma:
lekin kaise ..?
you can put the values of x and y given and you will see tht lhs is equal to rhs
Answered by
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Since two lines pass through a single point ( -6 , 2 ) .
So the lines have an unique solution and this they are intersecting .
As the lines are intersecting
:. a1/a2 ≠ b1/b2
So in both the questions the ratio of coefficient of x² and coefficient of x are not same so the equations are ---
1 . 2x² + 6x - 3
2 . 7x² + 2x + 8
HOPE IT HELPS !!!!!!!!!!!!!!!!!!!
So the lines have an unique solution and this they are intersecting .
As the lines are intersecting
:. a1/a2 ≠ b1/b2
So in both the questions the ratio of coefficient of x² and coefficient of x are not same so the equations are ---
1 . 2x² + 6x - 3
2 . 7x² + 2x + 8
HOPE IT HELPS !!!!!!!!!!!!!!!!!!!
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