Question

Find the equation of circle having centre (2,-5) and passing through point (3,2).

Answer 1

we can find radius by finding distance between these two points
$r = \sqrt{( - 5 - 2) {}^{2} + (2 - 3) {}^{2} } \\ = \sqrt{49 + 1} \\ r = \sqrt{50}$
equation of circle have centre(a,b) and radius r is given by
$(x - a) {}^{2} + (y - b) {}^{2} = {r}^{2}$
here (a, b) =(2,-5)
and r=√50
so eqn is
$(x - 2) {}^{2} + (y + 5) {}^{2} = 50$
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