Question

Find the equation of circle passes through (1,1) and (2,2)

Answer 1

Step-by-step explanation:

slope=y2 -y1 /x2 -x1= 2-1/2-1=1

equation

y-y1=slope(x-x1)

y-1=1(x-1)

x-y=0

Answer 2

Answer:

Step-by-step explanation:

treat that points as diametric end points

then

x-1*x-2+y-1*y-2=0

equation of line joining 1,1 and 2,2

x-y=0

by family of circles

x-1*x-2+y-1*y-2+lamda(x-y)=0