Question

Find the equation of circle passing through the point (3,4) (-3,4) and (3,-4)


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Answer 1

Answer

${x}^{2} + {y}^{2} - 25 = 0$

EXPLANATION

We know that

Equation of the required circle is

${x}^{2} + {y}^{2} + 2gx + 2fy + c = 0$

since (A) passes through (x1,y1) (x2,y2) and (x3,y3)

$x1 {}^{2} + y1 {}^{2} + 2fy1 + 2gx1 + c = 0</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>2</u><u>)</u><u>$

$x2 {}^{2} + y2 {}^{2} + 2fy2 + 2gx2 + c = 0.......(3)$

and

$x3 {}^{2} + y3 {}^{2} + 2fy3 + 2gx3 + c = 0.....(4)$

After solving

equation (1)-(2) and equation (3)-(4) we get value of g and f

See the attachment for the complete solution .

Answer 2

Answer:

heya !!

see the attachement