Question

find the equation of circle radius 3 and centre (2, -5)​

Answer 1

${x - 2}^{2} + {y + 5}^{2} = {3}^{2}$

${x}^{2} + {y}^{2} - 2x + 10y + 20 = 0$

Step-by-step explanation:

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Answer 2

Answer:

x²+y²-4x+10y+20=0

Step-by-step explanation:

Equation of a circle with radius 'r' and centre (a,b) is (x-a)² + (y-b)² = r²

Here, radius = r = 3 and centre (a,b) = (2,-5)

Therefore,

Equation of the circle = (x-2)² + {y-(-5)}² = 3²

(x-2)² + (y+5)² = 9

(x²-4x+4) + (y²+10y+25) = 9

x²+y²-4x+10y+29-9 = 0

x²+y²-4x+10y+20 = 0