find the equation of circle radius 3 and centre (2, -5)
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Step-by-step explanation:
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Answer:
x²+y²-4x+10y+20=0
Step-by-step explanation:
Equation of a circle with radius 'r' and centre (a,b) is (x-a)² + (y-b)² = r²
Here, radius = r = 3 and centre (a,b) = (2,-5)
Therefore,
Equation of the circle = (x-2)² + {y-(-5)}² = 3²
(x-2)² + (y+5)² = 9
(x²-4x+4) + (y²+10y+25) = 9
x²+y²-4x+10y+29-9 = 0
x²+y²-4x+10y+20 = 0
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