find the equation of circle touching y-axis at (0,3) and making an intercept of 8 units on the x-axis
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Rish08:
i did tht.. but it gets blur
oohkk..
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Equation of a circle touches the Y axis at (0,3) is
(x-a)^2 + (y-3)^2 = a^2
x^2 + y^2 — 2x×a- 6y + 9 = 0
since the length of intercepts on x axis of this circle is 8 unit
B.T.P
2(a^2-9)^(1/2) = 8
(a^2-9)=16
a^2= 25
a=5 (a>0)
Required equation is x^2+y^2– 10x-6y+9=0
(x-a)^2 + (y-3)^2 = a^2
x^2 + y^2 — 2x×a- 6y + 9 = 0
since the length of intercepts on x axis of this circle is 8 unit
B.T.P
2(a^2-9)^(1/2) = 8
(a^2-9)=16
a^2= 25
a=5 (a>0)
Required equation is x^2+y^2– 10x-6y+9=0
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