Question

Find the equation of circle which passes through the points (0, 0), (0, 1) and (2, 3).​

Answer 1

$\bold{\boxed{SØLŪTION}}$

Equestion is ,

y-0 =(1-0)/(0-0) × (x-0 )

=> y = 1/0 × X

=> y = X/0

=> X =0.----------(1)

then again ,

y-1= (3-1)/(2-0) × (X -0)

=> y-1 = 2/2 × X

=> y-1 = X ----------(2)

from 1 and two we find two equestions of the circle .....

and that are .....

(1) X= 0

(2) x-y+1=0

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