Question

Find the equation of circle whose center is C(2,-5) and which passes through (3,2)​

Answer 1

Answer:

    (x - 2)² + (y + 5)² = 50

Step-by-step explanation:

The equation of the circle with centre (a, b) and radius r is

    (x - a)² + (y - b)² = r²

We are given (a, b) = (2, -5).  What we need is r...

The radius is the distance from the centre to a point on the circle.

So r is the distance from the point (2, -5) to the point (3, 2).  Thus...

    r² = (3 - 2)² + (2 - -5)²  =  1² + 7²  =  1 + 49  =  50.

Therefor the equation of the circle is

    (x - 2)² + (y + 5)² = 50.