Question

Find the equation of circle with center (3,-2) and passing through the center of the circle x^2+y^2-6x+8y+9=0.

Answer 1

ANSWER

Given the equation of the circle is x

2

+y

2

−6x−8y+24=0

or, (x

2

−6x+9)+(y

2

−8y+16)−1=0

or, (x−3)

2

+(y−4)

2

=1

So, the centre is (3,4) and radius is 1.

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