Question

find the equation of circle with centre (2,2) and passes through point (4,5)​

Answer 1

Step-by-step explanation:

The centre of the circle is given as (h,k)=(2,2)

Since the circle passes through point (4,5), the radius (r) of the circle is the distance between the point (2,2) and (4,5).

r=√(2−4)2+(2−5)2 =√13

Thus, the equation of the circle is

(x−h) 2+(y−k)2 =r2

(x−2)2+(y−2)2 =13

x2−4x+4+y2−4y+4=13

x2+y2−4x−4y−5=0