Question

find the equation of circle with centre c and radius r where c=(2,_3),r=4​

Answer 1

Answer:

find the equation of circle with Centre c and radius r where c =

Answer 2

Answer:

x²+y²-4x-6y-3=0

Step-by-step explanation:

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where (h, k) is the center and r is the radius

Here

center (h, k) = (2, 3)

so h = 2 & k = 3

& radius(r) = 4

Putting in values

(x - 2)²+(y - 3)²  =  4²

(x - 2)(x - 2)+(y - 3)(y - 3) = 16

x² - 4x + 4+ y² - 6y + 9 =  16

x² + y² - 4x - 6y - 7 + 4 = 0

x² + y² - 4x - 6y - 3 = 0