Math, asked by RealBeast19, 1 month ago

Find the equation of circle x² + y² -8x -12y + 15 = 0 and passing through (5,4)

Answers

Answered by SaniyaGurav897
8

Answer:

Hey good night have a sweet dreams

Answered by sunilbhagya125
1

Step-by-step explanation:

x

2

+y

2

−8x−12y+15=0

comparing it with

x

2

+y

2

+2gx+2fy+c=0

we get g=−4 f=−6

so, centre of the required circle is (4,6)

distance between (4,6) and (5,4)

(5−4)

2

+(4−6)

2

=

1+4

=

15

so, radius of the required circle =

5

Hence, equation of the required circle is

(x−4)

2

+(y−6)

2

−(

5

)

2

=x

2

+16−8x+y

2

+36−12y=5

=x

2

+y

2

−8x−12y+47=0

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