Find the equation of circle x² + y² -8x -12y + 15 = 0 and passing through (5,4)
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Answered by
8
Answer:
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Answered by
1
Step-by-step explanation:
x
2
+y
2
−8x−12y+15=0
comparing it with
x
2
+y
2
+2gx+2fy+c=0
we get g=−4 f=−6
so, centre of the required circle is (4,6)
distance between (4,6) and (5,4)
(5−4)
2
+(4−6)
2
=
1+4
=
15
so, radius of the required circle =
5
Hence, equation of the required circle is
(x−4)
2
+(y−6)
2
−(
5
)
2
=x
2
+16−8x+y
2
+36−12y=5
=x
2
+y
2
−8x−12y+47=0
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