Question

find the equation of circles which pass through the point (3,6) and touch both axis​

Answer 1

Answer:

The equation of circle touching both axes is

x

2

+y

2

−2px−2py+p

2

=0________ (1)

since, the circle passes through point (3+6)

Therefore , (3)

2

+(−6)

2

−2p×3−2p×6+p

2

=0

9+36−6p−12p+p

2

=0

45−8p+p

2

=0

p=15,3

Hence, equation of the circle will be

x

2

+y

2

−6x−6y+9=0 or x

2

+y

2

−30x−30y+225=0