Question

① find the equation of circles with center is ( 2,-3) and radius is 4​

Answer 1

Answer:

$- 3$

this is the answer

Answer 2

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Given that:

Radius, r = 4, and center (h, k) = (-2, 3).

We know that the equation of a circle with centre (h, k) and radius r is given as

$\sf (x – h)^2 + (y – k)^2 = r^2 ….(1)$

Now, substitute the radius and center values in (1), we get

Therefore, the equation of the circle is

$\sf (x + 2)^2+ (y – 3)^2 = (4)^2$

$\sf x^2+ 4x + 4 + y^2 – 6y + 9 = 16$

Now, simplify the above equation, we get:

$\sf x^2 + y^2+ 4x – 6y – 3 = 0$

Thus, the equation of a circle with center (-2, 3) and radius 4 is $\sf x^2 + y^2+ 4x – 6y – 3 = 0$

Hope it's Helpful.....:)