Question

Find the equation of circum-cirle of the triangle formed by the straight lines given the following ​

Answer 1

1. Answer
2. :AB : x + 3y – 1 = 0 AB : x + 3y –1 = 0  AC : x + y +1 = 0  AC : x + y + 1 = 0  A : (1 – 2)  B : (– 5, 2)  BC : 2x + 3y + 4 = 0  BC : 2x + 3y + 4 = 0  C : (– 2, 1) Equation of circle x2 + y2 + 2gx + 2fy + c = 0  A, B, C are points on circumference.  ∴
3. 1 + 4 + 2g – 4f + c = 0 –– (i)  
4. 25 + 4 – 10g + 4f + c = 0 –– (ii)
5.  4 + 1– 4g + 2f + c = 0 –– (iii)  
6. Subtracting (i) – (iii) we get  6g – 6f = 0 (or) g = f –– (iv)
7. Subtracting (i) – (ii) we get 24 – 12g + 8f = 0 –– (v)
8. Solving (iv) and (v) we get  g = 6, f = 6, c = 7
9. Required equation of circle be  x2 + y2 + 12x + 12y + 7 = 0

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation: