Question

Find the equation of eircle whose radius is √58 units and the centre lies on the x-axis -
through the point 5,7​

Answer 1

Answer:

Given a circle of radius r=5

Given center lies on x-axis.

So, let the center be (h,0)

Equation of circle is

(x−h)

2

+y

2

=25 ....(1)

Since, it passes through (2,3)

⇒(2−h)

2

+3

2

=25

⇒(2−h)

2

=16

⇒2−h=±4

⇒h=−2,h=6

When h=−2, the equation of circle is

(x+2)

2

+y

2

=25

⇒x

2

+4x+4+y

2

=25

⇒x

2

+y

2

+4x−21=0

When h=6, the equation of circle is

(x−6)

2

+y

2

=25

⇒x

2

−12x+36+y

2

=25

⇒x

2

+y

2

−12x+11=0

Answer 2

Circle spelling wrong

Answer:

√58×5+√58×7

Step-by-step explanation:

I think this is correct

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